### Mathematics and Log Functions

To illustrate: b^xT - b^xA [approximately equal to] (log b)b^xT (x_T - x_A) Rel(b^xA) [approximately equal to] (log b)x_T Rel(x_A)(*) k = (log b)x_T (**) [Please see the attachment for the formatted question] Compare pi^100 to pi^100.1. Calculate these directly as accurately as you can. Then calculate Rel(pi^100.1)