Explore BrainMass

Explore BrainMass

    Chi-Squared Test

    BrainMass Solutions Available for Instant Download

    Chi square test for goodness of fit

    The personal manager of a firm is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly through the six-day work week. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: (Chi-S

    Chi square test for association

    In a study similar to one conducted by Fallon and Rezin (1985), a psychologist prepared a set of silhouettes showing different females body shapes ranging from somewhat thin to somewhat heavy and asked a group of women to indicate which body figure they thought men would consider the most attractive. Then a group of men were sh

    Chi-Square test for association

    Apparently there is a huge amount of misunderstanding concerning how the process of visual perception works. Specifically, many people believe (incorrectly) that at least part of looking at things involves energy going out of the eyes rather than energy coming into the eyes. This misunderstanding seems to be more common among

    Chi Square Tests

    I am having trouble completing this problem. I know what it is asking for but calculating it has me completely stuck. Please help!!!! Exam scores of 40 students in a statistics class are shown. (a) Estimate the mean and standard deviation from the sample. (b) Assuming that the data are from a normal distribution, define bin

    Chi Square Test: Exam Mark Case Study

    Prof. Green's multiple-choice exam had 50 questions with the distribution of correct answers shown below. Research question: At p<= .05, can you reject the hypothesis that Green's exam answers came from a uniform population Correct Answer Frequency A 8 B 8 C 9 D 11 E 14 Total 50

    Sample Chi - Square test.

    Using the following data, test the question that an equal number of Democrats, Republicans, and Independents voted during the election. Test the hypothesis at the .05 level of significance. Republican = 800 Democrat = 700 Independent = 900

    Equality of variance in Minitab

    Systolic Blood Pressure for Women: Systolic blood pressure results from contraction of the heart. Based on past results from the National Health Survey, it is claimed that women have systolic blood pressures with a mean and standard deviation of 130.7 and 23.4, respectively. Use the systolic blood pressures of women listed in th

    Chi squared non parametric measures

    7. A group of department store buyers viewed a new line of dresses and gave their opinions of them. The results were: Opinion Number of Buyers Opinion Number of Buyers Outstanding 47 Good 39 Excellent 45 Fair 35 Very good 40 Undesirable 34 Because the largest number (47) indicated the new line is outstanding, the head desi

    Chi square test.

    For many years TV executives used the guideline that 30 percent of the audience were watching each of the prime-time networks and 10 percent were watching cable stations on a weekday night. A random sample of 500 viewers in the Tampa-St. Petersburg, Florida, area last Monday night showed that 165 homes were tuned in to the ABC a

    Important information about Chi square test for goodness of fit.

    A group of department store buyers viewed a new line of dresses and gave their opinions of them. The results are below: Because the largest number (47) indicated the new line is outstanding, the head designer thinks that this is a mandate to go into mass production of the dresses. The head sweeper (who somehow became involved

    Chi Square

    Sixty-four students in an introductory college economics class were asked how many credits they had earned in college, and how certain they were about their choice of major. Research question: At &#945; = .01, is the degree of certainty independent of credits earned? Prof. Green's multiple-choice exam had 50 questions with th

    Chi Square: Random Samples of Different Scenarios

    1. A public policy researcher would like to know whether spending on cities and spending on the environment are statistically dependent. The following data were collected from a random sample of constituents in the voting district. 2. The US Department of Justice wanted to determine whether the sex of a person murdered is rel

    Hypotheis test: chi square

    A student team examined parked cars in four different suburban shopping malls. One hundred vehicles were examined in each location. Research question: At &#945; = .05, does vehicle type vary by mall location? Vehicles Vehicle Type Somerset Oakland Great Lakes Jamestown Row Total Car 44 49 36 64 193 Minivan 21 15 18 13 67 Fu

    Chi square: if there is no connection between weight and average number of hours spent watching TV, we should expect how many children to be spending 3-6 hours on average watching TV and who are more than 10 lbs. underweight?

    Recent studies have found that American children are more obese than in the past. The amount of time children spent watchitg television has received much of the blame. A survey of 100 ten-year-olds revealed the following data as shown in the table below with regard to weights and average number of hours a day spent watching tele

    Chi-Square Distributions

    The chi-square distribution can be used to test: a. the difference between two proportions. b. whether one proportion is higher than another. c. whethr two numerical variables are independent of each other. d. all of the above.

    Understanding chi-square distribution: A hypothesis test in Excel.

    There are three loan officers at Farmer National Bank. All decisions on mortgage loans are made by one of these officers. The president of the bank would like to be sure that the rejection rate is about the same for the three officers. A sample of 200 recent applications yielded the following results. Is the rejection rate relat

    A chi square hypothesis test in Excel...

    The manager of a Farmer Jack Super Market would like to know if there is a preference for the day of the week on which customers do their shopping. A sample of 420 families revealed the following. At the 0.05 significance level, is there a difference in the proportion of customers that prefer each day of the week? 1. State nu

    Construct a Hypothesis Test Using the Chi Square.

    Provide an example of how you could/would apply a hypothesis test using Chi Square? State the null and alternate hypotheses. You do not need to complete the entire five step process using actual numbers. Note there are no symbols used in stating a Chi Square type hypothesis - only words.

    Chi Square

    Provide an example of how you could/would apply a hypothesis test using Chi Square. State the null and alternate hypotheses. You do not need to complete the entire five step process using actual numbers. Note there are no symbols used in stating a Chi Square type hypothesis - only words.

    Chi Square Test of independence variables

    In a test of the independence of two variables, one of the variables has two possible categories and the other has tree possible categories. What will be the critical value of chi-square if the test is to be carried out at the 0.025 level? At the 0.05 level?

    Chi Square test of a Contingency Table

    In a chi-squared test of a contingency table, the value of the test statistic was =12.678, and the critical value at = 0.025 was 14.4494. Thus, a. we fail to reject the null hypothesis at  = 0.025 b. we reject the null hypothesis at  = 0.025 c. we don't have enough evidence to accept or reject the null hypothesis at

    P value for Chi square test

    A chi-square test for independence with 8 degrees of freedom results in a test statistic of 18.21. Using the chi-square table, the most accurate statement that can be made about the p-value for this test is that: a. p-value < 0.01 b. 0.025 > p-value > 0.01 c. 0.05 > p-value > 0.025 d. 0.10 > p-value > 0.05

    A chi square hypothesis test.

    A research organization has collected the following data on household size and telephone ownership for 200 U.S. households at the 0.05 level, are the two variables independent? Based on the chi-square table, what is the most accurate statement that can be made about the p-value for the test?

    Chi square distribution: probability statements.

    For df = 5 and the constant A, identify the value of A such that a. P(x^2 > A) = 0.90 b. P(x^2 > A) = 0.10 c. P(x^2 > A) = 0.95 d. P(x^2 > A) = 0.05 e. P(x^2 < A)f = 0.975 f. P(x^ < A) = 0.025 where x^2 is chi-squared.

    Chi-Square Testing

    The following data is taken from a customer satisfaction survey for a food product. Perform a Chi-square test to test the claim of whether a statistically significant relationship exists between the customer's satisfaction level and decision to repurchase the food item again. You may use the manual method of calculation, or sho

    Chi Square

    A personnel manager is concerned about absenteeism. She decides to sample the records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis to be tested is: Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are: Day of

    Chi square test for equality of variance

    Two samples of sizes 25 and 35 are independently drawn from two normal populations, where the unknown population variances are assumed to be equal. What are the number of degrees of freedom of the equal-variances t test statistic? When the necessary conditions are met, a two-tail test is being conducted to test the difference

    Conduct a hypothesis test to test for differences across groups.

    Refer to the attached schools data , which reports information on 94 school districts in northwest Ohio. a. Group the districts based on the percent of students on welfare: "low" (less than 5 percent), "moderate" (5 up to 10 percent), and "high" (10 percent or more). Conduct a test of hypothesis to determine whether the thre

    Hypothesis testing using Chi square distribution.

    A recent study by a large retailer designed to determine whether there was a relationship between the importance a store manager placed on advertising and the size of the store revealed the following sample information: Observed Frequencies (sample) Important Not Important Total Small