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    Chi square test for equality of variance

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    Two samples of sizes 25 and 35 are independently drawn from two normal populations, where the unknown population variances are assumed to be equal. What are the number of degrees of freedom of the equal-variances t test statistic?

    When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population means, but your statistical software provides only a one-tail area of 0.036 as part of its output. The p-value for this two - tail test will be:
    a. 0.018
    b. 0.009
    c. 0.072
    d. 0.964

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    Solution Preview

    Answer is 58
    [ d.f =n1+n2-2=35+25-2=58]
    You are essentially adding the ...

    Solution Summary

    The solution provides step by step method for the calculation of Chi square test for equality of variance. Formula for the calculation and Interpretations of the results are also included.