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    Chi-Squared Test

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    Which test should I do and why?

    Please help with the following problem. Need full and good explanation to my query. I am wondering which stats test to use: I am doing a project which is about whether sex ratio affects the occurrence of courtship behavior in a fish. I am also looking to see if the time at which the observations for each sex ratio affects

    2 Statistics problems (Chi-square test for independence )

    12.) For many years TV executives used the guideline that 30 percent of the audience were watching each of the prime-time networks and 10 percent were watching cable stations on a weekday night. A random sample of 500 viewers in the Tampa-St. Petersburg, Florida, area last Monday night showed that 165 homes were tuned in to the

    Chi square for a single nominal variable

    A director of an agency is hiring temporary help. In making plans, he has to know whether there isi any difference in the use of the agency at different seasons of the year. Last year there were 28 new clients in winter, 33 in spring, 16 in summer, and 51 in fall. On the basis of last years data, should the director conclude tha

    Calculation of one sample t test and Chi square test

    1. Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, a range of numbers for the P-value, critical value and state the final conclusion. Claim:- The mean bottom temperature of a fish breeding pond is less than 20 degree celcius. Sample Data:- n=56, x-bar =1

    Chi Square test of Independence for shoplifting data

    The chief of security for the Mall of the Dakotas was directed to study the problem of missing goods. He selected a sample of 100 boxes that had been tampered with and ascertained that for 60 of the boxes, the missing pants, shoes and so on were attributed to shoplifting. For 30 other boxes employees had stolen the goods, and fo

    Hypothesis testing

    Chapter 10, Exercise 22, page 343 Given the following hypothesis: A random sample of six resulted in the following values: 118, 105, 112, 119, 105, and 111. Using the .05 significance level, can we conclude the mean is different from 100? a. State the decision rule. b. Compute the value of the test statistic. c.

    Chi square analysis & ANOVA

    The data included for this assignment is the Major League Baseball data set. These data were collected on 23 June 2004 and represent the top 50 hitters in Major League Baseball. Use Excel to analyze the data. See attached Excel sheet of hitters and pitchers. 1. Chi square analysis - Do the top 50 hitters come predominan

    Hypothesis/ decision rule/ chi-square value

    The following hypotheses are given: Ho: Forty percent of the observations are in a category A, 40 percent are in B, and 20 percent are in c. H1:The observations are not as described in Ho We took a sample of 60, with the following results Category f0 A 30

    Chi Square test for Independence and Test of proportions

    On pg. 612 #4 The accuracy of Polygraph Tests The data in the accompanying table summarize results from tests of the accuracy of polygraphs (based on data from the Office of Technology Assessment). Use a 0.05 significance level to test claim that whether the subject lies is independent of the polygraph indication. What do the

    One criterion used to evaluate employees in the assembly section...

    One criterion used to evaluate employees in the assembly section of a large factory is the number of defective pieces per 1,000 parts produced. The quality control department wants to find out whether there is a relationship between years of experience and defect rate. Since the job is repetitious, after the initial training pe

    Chi square test for TV advertisement data

    Many companies use well-known celebrities as spokespersons in their TV advertisements. A study was conducted to determine whether brand awareness of female TV viewers and the gender of the spokesperson are independent. Each in a sample of 300 female TV viewers was asked to identify a product advertised by a celebrity spokesper

    Chi square test of independence, F test and ANOVA

    See attached file for full problem description. 1. A teacher figures that final grades in the statistics department are distributed as A-25%, B-25%, C-40%, D-5%, and F-5%. At the end of a randomly selected semester, the following number of grades were recorded. Determine if the grade distribution for the department is differe

    Student t test, chi-square test, z test

    1. Suppose that the scores of architects on a particular creativity test are normally distributed. What percentage of architects have z scores (a) above.10 (b0 below-10, (c) above .20, (d) below .20 (e) above 1.10, (f) below 1.10 (g) above -.10 (h) below -.10 ? 2. Suppose a candidate running for sheriff claims that she will

    Sampling error and chi-square test.

    8. A telephone survey utilized a sampling frame of 2000 numbers, and had a response rate of 25%. A question asked respondents if they preferred Brand 1, Brand 2, or Brand 3. According to the company, 35% of their customers preferred Brand 1, 35% preferred Brand 2, and 30% preferred Brand 3. The telephone survey found that 40%

    Statistics Questions

    1. How many different ways is it possible to get seven heads in a sample of twenty coin flips? 2.What is the probability of getting seven heads in a sample of twenty coin flips? Is this significantly different from the population in which P = 0.50 if the alpha is 0.05? 3. In which case would it be easier to reject the null

    Chi Square test of Independence

    I need to come up with a mean, standard deviation, histogram, and/or any other relevant calculations with the following data. Is this possible please show me what results you came up with and the process of retrieving those calculations. If not, what type of additional information is needed? Please show me examples and walk me t

    Goodness of fit test using Megastat

    The safety director of Honda USA took samples at random from the file of minor work related accidents and classified them according to the time the accident took place. Using the goodness-of-fit test and the .01 level of significance, determine whether the accidents are evenly distributed throughout the day. Write a brief e

    Do contributions to a social organization depend on income and/or age?

    A social organization was interested in determining if there were various demographic characteristics that might be related to people's propensity to contribute to charities. The organization was particularly interested in determining if individuals above 40 were more likely to contribute to larger amounts than individuals below

    ANALYSIS OF VARIANCE / NONPARAMETRIC METHODS: CHI -SQUARE APPLICATIONS

    ANALYSIS OF VARIANCE #10 The manager of a computer software company wishes to study the number of hours senior executives spend at their desktop computers by type of industry. The manager selected a sample of five executives from each of three industries. At the 0.05 significance level, can she conclude there is a difference in

    Chi-square Test: Goodness of Fit of a Poisson Distribution

    The Springfield Emergency Medical Service keeps records of its calls. A study of 150 five-minute time intervals resulted in the distribution of number of calls. Use a .01 level of significance and do a chi-square goodness of fit analysis for the data. Analyze the results and interpret what they mean. Use the 5-step hypothesis te

    Chi Squared Test for Card Holders Paying Charges

    The bank credit card department of Carolina Bank knows from experience that 5 percent of the card holders have had some high school, 15 percent have completed high school, 25 percent have had some college, and 55 percent have completed college. Of the 500 card holders whose cards have been called in for failure to pay their char

    Hypothesis Test Question with Conclusion

    The safety director of Honda USA took samples at random from the file of minor work-related accidents and classified them according to the time the accident took place. Time No. of Accidents Time No. of Accidents 8 up to 9 a.m. 61 up to 2 p.m. 7 9 u

    Difference in the Proportion of Viewers Watching the Channels

    In a particular market there are three commercial television stations, each with its own evening news program from 6:00 to 6:30 p.m. according to a report in this morning's local newspaper, a random sample of 150 viewers last night revealed 53 watched the news on wnae channel 5, 64 watched on wrrn channel 11, and 33 on wspd chan

    Testing of hypothesis and significance level - Chi square

    In a particular market there are three commercial television stations, each with its own evening news program from 6:00 to 6:30 P.M. According to a report in this morning's local newspaper, a random sample of 150 viewers last night revealed 53 watched the news on WNAE (channel 5), 64 watched on WRRN (channel 11), and 33 on WSPD

    Chi-square test for independence of variables and goodness of fit: 1) independence of variables: association between gender and seat belt usage 2) goodness of fit: does it appear that the sexes are equally probable

    5) Chi-square test for independence of variables and goodness of fit a) 1024 car drivers were classified according to gender and use of seat belts. The results are tabulated below: SEAT BELT USAGE DON'T USE USE MALE 192 272 FEMALE 284 276 Does the data suggest an association between gender and seat belt usage? b)

    Statistics Problems

    A) 100 students were classified according to their interest in statistics and their evaluation of the course. The results are tabulated below: HIGHLY INTERESTED INTERESTED INDIFFERENT NOT INTERESTED EXCELLENT 15 12 10 5 GOOD 10 10 5 5 ACCEPTABLE 5 10 8 5 Is there any evidence of association between interest in the topic an

    Chi square test of independence..

    In an epidemic of a certain disease, 920 children contracted the disease. Of these, 400 received no treatment, and of those, 98 suffered after-effects. Of the remainder who did receive treatment, 162 suffered after-effects. Show that chi squared = 4.90 and test the hypothesis that the treatment was not effective.

    Chi-Square Tests

    Question 1 a. State the hypothesis b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. In a recent study, the following percentages of U.S. retail car sales based on size were reported: 28.1%small, 47.8% midsize, 7% large, and 17.1% luxury. A recent survey of retail

    Question about Goodness of fit

    Classic Golf, Inc. manages five courses in the Jacksonville, Florida, area. The Director wishes to study the number of rounds of golf played per weekday at the five courses. He gathered the following sample information. Day Rounds Monday 124 Tuesday 74 Wednesday 104 Thursday 9