Purchase Solution

Chi square test for TV advertisement data

Not what you're looking for?

Ask Custom Question

Many companies use well-known celebrities as spokespersons in their TV advertisements. A study was conducted to determine whether brand awareness of female TV viewers and the gender of the spokesperson are independent. Each in a sample of 300 female TV viewers was asked to identify a product advertised by a celebrity spokesperson. The gender of the spokesperson and whether or not the viewer could identify the product was recorded. The numbers in each category are given below.

Male Celebrity Female Celebrity
Identified Product 41 61
Could Not Identify 109 89

Referring to the table above, at 5% level of significance, the critical value of the test statistic is
A. 3.8415
B. 5.9914
C. 9.4877
D. 13.2767

Attachments
Purchase this Solution
Solution Summary

The solution gives the critical value of a Chi-square test.

Solution Preview

Please see the attached file.

Many companies use well-known celebrities as spokespersons in their TV advertisements. A study was conducted to determine whether brand awareness of female TV viewers and the gender of the spokesperson are independent. Each in a sample of 300 female TV ...

Purchase this Solution
Free BrainMass Quizzes
Measures of Central Tendency

This quiz evaluates the students understanding of the measures of central tendency seen in statistics. This quiz is specifically designed to incorporate the measures of central tendency as they relate to psychological research.

Know Your Statistical Concepts

Each question is a choice-summary multiple choice question that presents you with a statistical concept and then 4 numbered statements. You must decide which (if any) of the numbered statements is/are true as they relate to the statistical concept.

Measures of Central Tendency

Tests knowledge of the three main measures of central tendency, including some simple calculation questions.

Terms and Definitions for Statistics

This quiz covers basic terms and definitions of statistics.

View More Free Quizzes
Related BrainMass Solutions

  • Measuring Association of age group v where people get their news

    For this we have to use chi-square test of independence. Null Hypothesis The characteristics 'age group' and 'source of news' are independent. Alternative Hypothesis The characteristics are not independent.

  • chi-square test

    In a chi-square test, normal distribution of deviations (observed minus expected values) is assumed; so it is a nonparametric test in the sense that is does not assume the parameter of normal distribution for the data.

  • Statistics - Hypothesis Test using the Chi Square

    14% Cable observed, 10% of 500 = 50 expected The Chi square test statistic for this data (Chi square calculator) is 14.32 Since the test statistics 14.32 > 7.82, the Null is rejected.

  • 8 Hypothesis Testing Questions

    Solution: Response Observed Expected Chi-square Yes don't 55 50 0.5 No do 45 50 0.5 Total 100 100 1 Since at the 0.05 level of significance with one degrees of freedom the chi-square value is 3.841 and the calculated chi-square

  • Chi-square test for independence

    95127 2 Statistics problems (Chi-square test for independence ) 12.)

  • Testing whether means are different - ANOVA and Chi-Square

    44465 Test for difference in mean using ANOVA and Chi Square There are three hospitals in the Tulsa, Oklahoma, area. The following data show the number of outpatient surgeries performed at each hospital last week.

  • Basic Statistics and Probability

    Answer Chi square test can be applied to check whether there is any a difference in the proportion of viewers watching the three channels. H0: There is no significant difference in the number of views for the 3 channels.

  • Hypothesis

    How many degrees of freedom will the test have? e. Without collapsing any cells, calculate the value of the chi-square test statistic. f. At the 0.05 level of significance, are type of advertisement and age of customer independent? g.

  • Chi-square statistics and non-parametric tests

    Please see the attached file for response. -------------------------------------------------- Chi-square Why do you use the chi-square statistics?

View More Related Solutions