### Volume of a box

An open box with a square base is to be built for $48. The sides of the box will cost $3 per square meter, and the base will cost $4 per square meter. Express the volume of the box as a function of the length of its base.

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An open box with a square base is to be built for $48. The sides of the box will cost $3 per square meter, and the base will cost $4 per square meter. Express the volume of the box as a function of the length of its base.

Let F be the Fibonacci sequence n F = 1, F =1 0 1 F + F n-1 n-2 show 1) For all of n, F = (7/4) ^ n n 2) n+1 n+1 F = 1/√5 ((1+√5) - (1-√5) )

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Solve the following equation by completing the square. See Attached for equation

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Solve for y. Watch for extraneous solutions. See attachment for equation

Solve for x. Watch for extraneous solutions (See attachment for details)

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Here's the formula... The answer should be 4, which should be W S=10 T=5 w=4 w=33-(10 - 0.28 x S + square root of 28xS ) x ( 33 - T ) / 22.727 so.. the square root symbol was over top of 28 and S just don't know how to put that symbol in here... so.. you work from left to right... and you do what's in the ( )

Factorize the following equation (with steps please) - see attachment

x^3 + x^2 - x - 1

Application Problem 2M (MOTION PROBLEM) Janet drove 120 miles at x miles per hour (m/hr) before 6:00 A.M. After 6:00 A.M., she increased her speed by 5 miles (m) per hour and drove 195 additional miles. Write an expression for: The time spent driving before 6:00 A.M. The time spent driving after 6:00 A.M. The total dri

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Which of the following expressions would help estimate Please see attachment

1. Tom planted a bamboo on June 1st that was eight feet tall. In June it grew at the rate of five inches per day. Find the equation of the line that shows how tall the bamboo was each day in June. 2. Find the equation of the line that passes through the points (4,-2) and (2,4). 3. Find the equation of the line that passes thr

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The two equations are as follows: x+y=48 12x+14y=628 Please help. Thank you.

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Solve for a and b 4a + b = 1 (mod 5) a + b = 2 (mod 5) check answers for a and b by substituting into the original equations