Find the points of intersection (if any) of the given pair of curves and draw the graphs. Y= x^2 and y= 2x+2
Give an example of a non-rectifiable closed Jordan curve on the interval -1<=t<=1. My thought: t + i(sin 1/t) + ????? Please advise what curve I can add to make this work. Or, if this will not work, please provide an example of a non-rectifiable closed Jordan curve on -1<=t<1.
#26 Please see the attached file for full problem description.
Two people 1.8m tall walk from each other until they can no longer see each other (due to the curvature of the earth which has a radius of 6378km). Assuming nothing else blocks their view, how far do they have to walk? Note. I cant get my head around how this relates to what we've lear
Find the length of the curve y=cosh(x) between x=-1 and x=2 Find the length of y=cosh x for -1 ≤ x ≤ 2. The length of the curve will be given by : = sinh x Length = Integral is given by : Therefore length = = .0528
Differential Geometry (I) Curves in Space Curvature of the Curve Torsion of the Curve For the curve r = ( √6 at^3, a(1+3t^2), √6 at ) Show that k = - T = 1/[a(3t^2 + 1)^2] where k = curvature of the curve, T = tors