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Oxidation-Reduction and Electrochemistry

Reduction Through Constant Current Electrolysis

Reduction through constant current electrolysis a) How much Cr3+ was reduced to Cr2+? b) A few seconds after the electrolysis was stopped, the potential of the cell came to rest at -0.524 volts. How much Cr3+ actually remains in the solution? c) What was the original Cr3+ concentration?

Oxidizing and Reducing Agents

In the following reaction, identify the oxidizing and reducing agents. Cd + NiO2 + 2H2O to Cd(OH)2 + Ni(OH)2 a) Cd+2 is the reducing agent, NiO2 is the oxidizing agent. b) Cd is the reducing agent, H2O is the oxidizing agent. c) Cd is the reducing agent, NiO2 is the oxidizing agent. d) Cd is the reducing agent,

Identifying oxidizing and reducing agents

6. In the following reaction, identify the oxidizing and reducing agents. 3Ca + VO3 --> 3CaO + V a. Ca+2 is the reducing agent, VO3 is the oxidizing agent b. Ca is the oxidizing agent, VO3 is the reducing agent c. Ca is the reducing agent, V is the oxidizing agent d. Ca is the reducing agent, O-2 is

Molarities of Zinc and Silver Ions in an Electrochemical Cell

It is given that the electrochemical cell is at 298K. At time zero [Zn 2+ ]= 1.0 x 10 ^-3 M and [Ag +] = 0.500 M. Calculate the molarities of zinc and silver ions after a current of 2.00 amperes flow for 20 hours. Please show step by step and the units you are using.