# Isomerization of a Phosphorylated Glucose Molecule

The isomerization of a phosphorylated glucose molecule from 1-p to 6-p form with standard free energy change=-1.74kcal/mole. Find the equilibrium concentration ratio of glucose-p in the two isometric states.

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#### Solution Preview

The relationship between the free energy change (DG) and the equilibrium concentration ratio (K) is:

DG = -RT ln K

T = absolute temperature. 298 K is standard but 310 K is ...

#### Solution Summary

Answer is found using the formula DG = -RT ln K, representing the relationship between the free energy change (DG) and the equilibrium concentration ratio (K).

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