The isomerization of a phosphorylated glucose molecule from 1-p to 6-p form with standard free energy change=-1.74kcal/mole. Find the equilibrium concentration ratio of glucose-p in the two isometric states.© BrainMass Inc. brainmass.com October 9, 2019, 4:15 pm ad1c9bdddf
The relationship between the free energy change (DG) and the equilibrium concentration ratio (K) is:
DG = -RT ln K
T = absolute temperature. 298 K is standard but 310 K is ...
Answer is found using the formula DG = -RT ln K, representing the relationship between the free energy change (DG) and the equilibrium concentration ratio (K).