# Working with a sinusoidal function

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This question concerns the function

y/3 = 3+ 4sin [3x+ pi ]

Where x is measured in radians.

(1) Choose the one option which gives the value of the function when x= pi/2

(2) Choose the one option which gives the period of the function.

Options for questions 1 and 2.

A 1

B. 2

C. 3

D. 4

E. pi/3

F. 2pi/3

G. pi

H. 3pi

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##### Solution Summary

A thorough answer with all mathematical steps. The sinusoidal function values are examined. The period of the functions are determined.

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(1)

our function is

y/3 = 3+ 4sin [3x+ pi ]

when x=pi/2

We have, 3x + pi = (3pi/2)+pi = 5pi/2 = (2pi + pi/2)

Sin function repeats itself when we add 2pi to it

Hence Sin(2pi + pi/2)= Sin(pi/2) = 1

Substitute this value back to the given function and find the value of y.

y/3 = 3+ 4sin ...

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