# General Math and Real World Application

Problem Remember to simplify all answers

1. a) Give the place value of 9 in 4,938,300.

b) Give the place value of 7 in 54,763

2. a) Name the property of addition that is illustrated.

4 +15 = 15 +4

b) Name the property of multiplication that is illustrated.

6 x 5 = 5 x 6

3. Perform the indicated operations

687

902

673

+204

4. Evaluate the expression

5. Evaluate the expression

6. Find the product.

189

x59

7. Divide, using long division

8. Find the prime factorization for 264.

9. Find the greatest common factor (GCF) for the given numbers. 36 and 108.

10. Convert the fraction to a mixed number

11. Use the cross-product method to find out whether the pair of fractions is equivalent.

12. Multiply

13. Divide

14. Subtract

53,294 - 41,074

15. Estimate the sum by rounding each addend to the nearest hundred.

843

3,291

278

2,912

+_ 576

Real World Applications

(Remember to show all steps.)

16. A truck rental firm has ordered 35 new vans at a cost of$13,350 per van. What will be the total cost of the order?

17. What is the cost of pounds (lb) of grapes if the price per pound is 68 cents?

18. A bookshelf is 86 in. long. If the thickness of each book on the shelf is inches, how many books can be placed on the shelf?

19. Eight people estimate that the total expenses for a trip they are planning to take together will be $1,824. If each person pays an equal amount, what will be each person's share?

20. Shawn makes $235 a day on a job. How much will he earn for working day?

21. A garden measures 6 ft by 7 ft needs fencing.

If the fencing costs $8 per square foot, how

much will it cost to put fencing around the

garden?

22. Find the perimeter of the figure shown..

3.6 m

3.6 m 3.6m

3.6m 3.6m

3.6 m

23. Find the perimeter of the figure.

5.5 in

4 in

3.2 in

24. Find the area of the given figure.

6 ft

3ft

15 ft 7ft

25. Find the volume of the given figure.

6 ft

8 ft

15 ft

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#### Solution Summary

This solution is comprised of step-by-step calculation and detailed explanation of each problem.

Imaginary ( Complex ) Numbers, Discriminants and Real World Applications

1. When solving a quadratic equation using the quadratic formula, it is possible for the b2 - 4ac term inside the square root (the discriminant) to be negative, thus forcing us to take the square root of a negative number. The solutions to the equation will then be complex numbers (i.e., involve the imaginary unit i).

Question:

In the real world, where might these so-called imaginary numbers be used?

2. When using a formula, we often know the value of one variable to a greater degree of accuracy than we know the others. In your opinion, what affect, if any, does it make on our use of a formula if we know the value of one variable to a greater degree of accuracy than another?