# Probability

Question: Urn I has 2 white and 3 black balls; Urn II, 4 white and 1 black; and Urn III, 3 white and 4 black. An urn is selected at random and a ball drawn at random is found to be white. Find the probability that Urn I was selected.

Answer: 14/57

https://brainmass.com/statistics/bayesian-probability/probability-bayes-theorem-26754

#### Solution Preview

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2. send solution as attachment

3. Use words to explain solutions. DO NOT RELY ONLY ON ALGEBRAIC MANIPULATIONS/ OR SYMBOLS.

HERE ARE THE ANSWERS; SHOW ME HOW YOU GET THE SOLUTION...IN OTHER WORDS, JUST DO THE PROBLEM. But if your solution is not the same, then do not respond!

It is a baye's theorem ...

#### Solution Summary

Please use words to explain solutions (do not rely only on algebraic manipulation or symbols).

Question: Urn I has 2 white and 3 black balls; Urn II, 4 white and 1 black; and Urn III, 3 white and 4 black. An urn is selected at random and a ball drawn at random is found to be white. Find the probability that Urn I was selected.

Answer: 14/57