Starting from rest at a height equal to the radius of the circular track, a block of mass 30 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient mu). The radius of the track is 35 m.
The acceleration of gravity is 9.8 m/s^2.
If the kinetic energy of the block at the bottom of the track is 4800 J, what is the work done against friction? Answer in units of J.© BrainMass Inc. brainmass.com March 4, 2021, 11:29 pm ad1c9bdddf
At the top of the track before sliding:
The potential energy of the block: PE = mgr (using the bottom of the track as the reference).
The kinetic energy of the block KE = 0.
So the total energy of the ...
It finds the work done against friction when the block slides down a quarter circular track. The solution is detailed and well presented.