Suppose the roller coaster in Fig. 8-29 (attached) (h1 = 32 m, h2 = 13 m, h3 = 20) passes point A with a speed of 3.00 m/s. If the average force of friction is equal to one fifth of its weight, with what speed will it reach point B? The distance traveled is 55.0 m.
distance travelled s= 55.0 m
initial speed u = 3.00 m/s
final speed at B (v) = ?
gravitational acceleration g = ...
The solution shows the values to use and then puts them to use in the relevant formula and follows through the calculations to clearly display how to find the speed of a roller coaster at a specified point under the conditions laid out in the question.