1: A plane is inclined at an angle of 30 deg. w/ respect to the horizon. A block of mass 6.0 kg is placed at the bottom of the plane and given an initial velocity of 3.0 m/sec up the plane. The coefficient of friction between the block and plane is 0.25.
a) How far up the plane will the block go?
b) Assuming the block slides back down the plane, how fast will it be going when it returns to the bottom?
Normal reaction of plane on block = m*g*cos(theta), here theta = 30deg.
therefore friction force f = mu*m*g*cos(theta) downward along the plane)
let the block goes up along the plane a distance ...
The solution shows all the calculations necessary plus an explanation of the problems.