Block sliding down an inclined plane
A block slides down an incline (see the fig. in the attachment). As it moves from point A to point B, which are 6.6 m apart force F acts on the block, with magnitude 3.3 N and directed down the incline. The magnitude of the frictional force acting on the block is 6.1 N. If the kinetic energy of the block increases by 28 J between A and B, how much work is done on the block by the gravitational force as the block moves from A to B?
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Solution Preview
Please see the attached file.
The diagram shows various forces acting on the block.
mg = weight of the block acting vertically downwards which is resolved into components mgcosθ perpendicular to the inclined plane and mgsinθ parallel to the inclined plane.
F = Applied force parallel to the inclined plane (down the plane) = 3.3 N
f = Frictional force parallel to the inclined plane (up the plane) = 6.1 N
Let the ...
Solution Summary
The expert examines the block sliding down an inclined plane. A problem solved step by step.