# Block and Inclined Plane

A block is on an inclined plane. There is a horizontal force on the block. The block is at rest. There is a certain coefficient of friction.

a) find force (magnitude and direction)

b) find normal force exerted on the block by the plane

Given: you can give the block a mass of 5.00 kg an angle of 60 degrees and the coefficient of friction 0.300

Please see the attachment.

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#### Solution Preview

Please see attachment.

Here is solution to this problem:

Let the inclined plane make an angle of 60 degrees with the horizontal.

let the value of g be 10 m/s^2.

Weight of the block acting vertically downward = mg = 5*10 = 50 N

Component of mg(50N) parallel and down the inclined plane = mg sin 60

Component of mg(50N) normal to the inclined plane(pressing the plane) = mg cos 60

Let the horizontal force F be applied to the ...

#### Solution Summary

Resove gravitational force acting on the block kept on the inclined plane in two components; one parallel to the plane and the other perpendicular to the plane.