Explore BrainMass
Share

Explore BrainMass

    Block and Inclined Plane

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    A block is on an inclined plane. There is a horizontal force on the block. The block is at rest. There is a certain coefficient of friction.

    a) find force (magnitude and direction)
    b) find normal force exerted on the block by the plane

    Given: you can give the block a mass of 5.00 kg an angle of 60 degrees and the coefficient of friction 0.300

    Please see the attachment.

    © BrainMass Inc. brainmass.com October 9, 2019, 10:18 pm ad1c9bdddf
    https://brainmass.com/physics/applied-physics/force-block-inclined-plane-example-215780

    Solution Preview

    Please see attachment.
    Here is solution to this problem:

    Let the inclined plane make an angle of 60 degrees with the horizontal.
    let the value of g be 10 m/s^2.
    Weight of the block acting vertically downward = mg = 5*10 = 50 N
    Component of mg(50N) parallel and down the inclined plane = mg sin 60
    Component of mg(50N) normal to the inclined plane(pressing the plane) = mg cos 60

    Let the horizontal force F be applied to the ...

    Solution Summary

    Resove gravitational force acting on the block kept on the inclined plane in two components; one parallel to the plane and the other perpendicular to the plane.

    $2.19