A block slides down from rest from the top of an inclined plane 30° above the horizontal. The plane is 100ft long and frictionless. What distance will it travel on a frictionless horizontal surface at the first of the plane 6.00s after it has traveled from rest?
Acceleration in the inclined plane is a = g = 32ft/s²
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Since the inclined plane is frictionless, the component of g along the plane = g sin theta = 32 sin 30 = 16 ft/s^2
For the motion along the inclined plane, u = ...
Neat, step-by-step solution is provided regarding translational motion.