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Physics - Translational Motion

A block slides down from rest from the top of an inclined plane 30° above the horizontal. The plane is 100ft long and frictionless, What distance will it travel on a frictionless horizontal surface at the first of the plane 6.00s after it has traveled from rest?

Acceleration in the inclined plane is a = g = 32ft/s²

Please explain.

Solution Preview

Since the inclined plane is frictionless, the component of g along the plane = g sin theta = 32 sin 30 = 16 ft/s^2

For the motion along the inclined plane, u = ...

Solution Summary

Neat, step-by-step solutio is provided.