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Physics around an Object Towed up and Incline

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An object on an incline of 30 degrees is towed up the incline by an applied force of 100N. The coefficient of kinetic friction of mu=.35. The mass of the object is 10.0kg.

PART I
1) Draw a sketch
2) Draw a free body diagram
3) What is the weight of the object?
4) What is the acceleration of the object in the y direction?
5) Write Newtons 2nd Law for the x and y directions
6) What is the Magnitude of the friction force?
7) What is the acceleration of the object along the incline?
8) if the object starts from rest, what is its speed at 10m. along the incline

PART II
1) Write the conservation of energy equation.
2) Find the work done by the friction force
3) Find the work done by the applied towing force
4) Find the velocity at the top (10m. along the incline)
5) Find the objects acceleration alond the incline.
6) Find the work done by the gravitational force (check to see if it is equal to delta Potential Energy= Potential Energy final-potential energy initial)
7) Do your numbers agree wit the Work-Kinetic Energy theorem? w= delta Kinetic Energy prove this showing numbers.

Solution Summary

The solution gives step-by-step workings on how to find out many features of the described object being dragged up an incline, including momentum, work done, velocity and more. Includes a free body diagram of the situation.

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PART I:

1.)
For sketch see the attachment.

2.)

3.)
inclination of plane with horizontal (theta = Q) = 30 degree
Force acting on object = F = 100 N
Coeff. of kinetic friction = mu = 0.3
mass of object = m = 10 kg

wight of object W = m*g = 10*9.8 = 98 N

4.)
I'm assuming y-direction to be perpendicular to the plane and x-direction along the plane.

Because, along y-direction the object can't move hence, the acceleration along y-direction will be 0 (zero).

5.)
Perpendicular to the plane (y-direction), by Newton's 2nd law,
Fy = m*ay
=> N - W*cos(Q) = 0 --Answer
=> N = W*cos(Q) = 98*cos(30) = 98*0.866 = 84.868 N .....(1)

Along the plane (x-direction), by Newton's 2nd law,
Fx = m*ax
=> F - ...

Solution provided by:
Education
• MSc , Pune University, India
• PhD (IP), Pune University, India
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