A jack-screw has a handle 35 inches long and a pitch of 7/32 inches. If a pull of 15 lbs. is required at the end of the handle to lift a 3,000 lbs. load, what is the force expended to overcome friction?© BrainMass Inc. brainmass.com March 22, 2019, 1:22 am ad1c9bdddf
Applied force (Fa) = 15 lbs
Handle length (R) = 35 inches
Load to be lifted (W) = 3 lbs
Pitch (p) = 7/32 inches
This problem can be solved using work and ...
In this problem we estimate friction force when a jack screw is lifted up with a handle of given length. To solve this problem, a concept of law of conservation mechanical energy is applied.