1.) A horizontal force of 3.00 N is applied to a 1.00-kg radio, initially at rest on a table with a level surface.
a.) Will the radio move if the coefficient of the friction is 0.45?
b.) What is the coefficient of friction if it just begins to move?
c.) What is its acceleration if the coefficient of the friction is only 0.02?
a. For the radio to move, the 3 N force must overcome the force of static friction. If they are just equal, the radio will not move.
The force of friction is equal to the normal force times the coef. of friction. Or...
Ff = Fn*u
Where Ff ...
The solution carefully explains and solves each part of the problem.