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The double pulley below has a moment of inertia of 50 kgm2 and is initially at rest. The outside radius is 500 mm and the inner radius is 250 mm.
a) Find the angular acceleration of the pulley.
b) Find the angular velocity of the pulley after point A on the cord has moved 3.5 m.
Let us assume the angular acceleration of the pulley = alpha
Hence, the linear acceleration of the block a = alpha*ri
ri = 250 mm = 0.25 m
ro = 500 mm = 0.50 m
mass of the block m = 80 kg
moment of ...
This solution is provided in 175 words. It uses step-by-step equations to solve for angular acceleration and velocity.