In Fig. 11-42, one block has a mass M = 500 g, the other has mass m = 460 g, and the pulley, which is mounted in horizontal frictionless bearings, has a radius of 5.00 cm. When released from rest, the heavier block falls 81.5 cm in 2.90 s (without the cord slipping on the pulley).
(a) What is the magnitude of the block's acceleration? _______m/s2
(b) What is the tension in the part of the cord that supports the heavier block? _______N
(c) What is the tension in the part of the cord that supports the lighter block? _______N
(d) What is the magnitude of the pulley's angular acceleration?
(e) What is its rotational inertia?
The general equation relating constant acceleration a, to position y, time t, and initial velocity vo, is:
(1) y= vo t + .5 a t^2 in which vo=0.
In (1), knowing y and t and vo, you should substitute knowns to find:
(a) ANSWER acceleration (2) a= .194 nt/kg or .194 m/sec^2
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This solution is provided in 300 words and gives step-by-step equations to find each of the answers to the missing information from the question.