A 3.50 kg counterweight is attached to a light cord, which is wound around a spool . The spool is a uniform solid cylinder of radius 8.00 cm and mass 1.40 kg.

(a) What is the net torque on the system about the point O?

(b) When the counterweight has a speed v, the pulley has an angular speed w= v/R. Determine the total angular momentum of the system about O.

(c) Using the fact that torque = dL/dt and your result from (b), calculate the acceleration of the counterweight.

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...Torques due to forces N2 and F about point P ... Direction of the torque vector is given by the ... Newton's laws of rotational motion: By analogy with the Newton's ...

...Rotational motions diagrams are provided for slender rods ... Solution: By Newton's second law, as applied to the rotational motion, applied torque is equal ...

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... ½ Iω2 Angular momentum L = Iω Impulsive torque τ ∆t. ... which we learned for linear motion, are in ... the same form as similar equations for rotational motion. ...

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... Since we consider the rotation as being about the center ... in a direction to provide the torque necessary to ... can be in the direction of motion (rolling downhill ...

... distance from the point of application to the point of rotation. ... αt + ω0 v = at + v0 Equations of motion with constant ... τ = Iα Force/Torque F=Ma. ...

... Thus, the hip adduction torque probably acts to control ... of the series of planar motions (the hip ... hand, may allow the hip external rotation motion to increase ...

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