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Angular acceleration

In a pulley system, the time of descent of a 100 gram mass is found to be 35 seconds. The vertical distance is given as 120 cms. The radius of the pulley (in the form of a disc) is 5 cms. Mass of the pulley is unknown. Determine (a) angular acceleration of the pulley (b) number of revolutions it makes during this time (c) Torque acting on the pulley. (d) Mass of the pulley.

Solution Preview

(a) angular acceleration of the pulley
a=alpha r
r= 5 cm= 0.05 m
alpha = angular acceleration= a/r

x=ut+1/2 a t^2

u= 0 m/s assuming the mass starts with a zero velocity at time ...

Solution Summary

Calculates (a) angular acceleration of the pulley (b) number of revolutions it makes during this time (c) Torque acting on the pulley, (d) Mass of the pulley.

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