Sketch parabola first finding the vertex, foci and directrix for this equation y+3=1/8(x-5)squared meaning the (x-5) part of equation is squared.
Equation of parabola,
(y+3) = (1/8)*(x-5)^2
(x-5)^2 = 8*(y+3) ..(1)
can be written by transforming the axes to (X,Y),
X^2 = ...
A parabola is sketched by finding vertex, foci and directrix. These are shown on the graph, too.