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Trigonometry Problems

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E= {(x,g(x)): (-3,-7), (-1,-3), (0,-1), (2,3), (4,7)}
Write the rule for g-1(x):

Show that csc[arccos x] = 1/ root(1-x2):

sin 0=.4910; angle 0 =

sec(-38 degrees 22') =

If F(x) = log5 2x, find F-1(x)._________

Find (a) an upper limit and (b) a lower limit for the zeros of the function P(x)....zeros= -3/2, -root 5-1/2, and root 5+1/2..____________

tan 210 degrees + cot 240 degrees/1+tan 300 degrees cot(-60 degrees)

Write a trigonometric equation for cos using
A=-2, period= pie/4, phase shift= -pie/2_____________

Find the values of the six trigonometric functions of 0 if 0 is an angle in standard position with T(-20,-21) on its terminal ray.

a. 0 is located in which quadrant?
b. sin 0=
c. cos 0=
d. tan 0=
e. csc 0=
f. sec 0=
g. cot 0=

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E= {(x,g(x)): (-3,-7), (-1,-3), (0,-1), (2,3), (4,7)}
Write the rule for g-1(x):

Rule for g-1(x) = {(g(x), x): (-7, -3), (-3, -1), (-1, 0), (3, 2), (7, 4)}

Show that csc[arccos x] = 1/ root(1-x2)

Let arcosx = y

 cosy = x
 cscy =

Now, csc[arccos x]

= cscy


Hence proved.

sin θ = .4910; angle θ = 29°41'

sec(-38 degrees 22') = 1.275 (rounded to ...

Solution provided by:
  • BSc, Meerut University
  • MSc, Meerut University
  • MPhil, Institute of Advanced Studies
  • MSc, AIT
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