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    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    E= {(x,g(x)): (-3,-7), (-1,-3), (0,-1), (2,3), (4,7)}
    Write the rule for g-1(x):

    Show that csc[arccos x] = 1/ root(1-x2):

    sin 0=.4910; angle 0 =

    sec(-38 degrees 22') =

    If F(x) = log5 2x, find F-1(x)._________

    Find (a) an upper limit and (b) a lower limit for the zeros of the function P(x)....zeros= -3/2, -root 5-1/2, and root 5+1/2..____________

    evaluate:
    tan 210 degrees + cot 240 degrees/1+tan 300 degrees cot(-60 degrees)

    Write a trigonometric equation for cos using
    A=-2, period= pie/4, phase shift= -pie/2_____________

    Find the values of the six trigonometric functions of 0 if 0 is an angle in standard position with T(-20,-21) on its terminal ray.

    a. 0 is located in which quadrant?
    b. sin 0=
    c. cos 0=
    d. tan 0=
    e. csc 0=
    f. sec 0=
    g. cot 0=

    © BrainMass Inc. brainmass.com December 24, 2021, 8:30 pm ad1c9bdddf
    https://brainmass.com/math/trigonometry/trigonometry-problems-283774

    SOLUTION This solution is FREE courtesy of BrainMass!

    E= {(x,g(x)): (-3,-7), (-1,-3), (0,-1), (2,3), (4,7)}
    Write the rule for g-1(x):

    Rule for g-1(x) = {(g(x), x): (-7, -3), (-3, -1), (-1, 0), (3, 2), (7, 4)}

    Show that csc[arccos x] = 1/ root(1-x2)

    Let arcosx = y

     cosy = x
     cscy =

    Now, csc[arccos x]

    = cscy

    =

    Hence proved.

    sin θ = .4910; angle θ = 29°41'

    sec(-38 degrees 22') = 1.275 (rounded to 3 decimal places)

    If F(x) = log5 2x, find F-1(x)._________

    Let F(x) = y

    y = log5 2x

    Solve it for x

    Now replace x by y and y by x

    Thus,

    Find (a) an upper limit and (b) a lower limit for the zeros of the function P(x)....zeros= -3/2, -root 5-1/2, and root 5+1/2..____________

    I think the roots should be

    Roots will lie between -2<x<1

    (a) Upper limit = 1
    (b) Lower limit = -2

    evaluate:
    tan 210 degrees + cot 240 degrees/1+tan 300 degrees cot(-60 degrees)

    Write a trigonometric equation for cos using
    Amplitude = -2, period = pie/4, phase shift= -pie/2_____________
    y = Acos(Bx + C), where a is the amplitude. The period is given by 2pi/b and the number -C/B is the phase shift

    Given period = pie/4

    Phase shift= -π/2

    -C/B = -π/2

    C = (π/2)*8 = 4π

    Thus, y = -2cos(8x + 4π)

    Find the values of the six trigonometric functions of 0 if 0 is an angle in standard position with T(-20,-21) on its terminal ray.

    a. 0 is located in which quadrant? III rd quadrant
    b. sin θ = -21/29
    c. cos θ = -20/29
    d. tan θ = 21/20
    e. csc θ = -29/21
    f. sec θ = -20/20
    g. cot θ = 20/21

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 8:30 pm ad1c9bdddf>
    https://brainmass.com/math/trigonometry/trigonometry-problems-283774

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