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Solving Triangular Equation in Satellite Example

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A satellite circles the earth in such a manner that it is y miles from the equator (north or south, height from the surface not considered) t minutes after its launch, where y=5000[cos( π/45)(t-10)]. At what times t in the interval [0,240], the first 4 hours is the satellite 3000 mi north of the equator?

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Solution Summary

The solution gives detailed steps on solving a triangular equation with a satellite example.

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Since y=5000[cos((t-10)π/45)], plug y=3000 to get ...

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