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Period of the motion of a satellite orbiting above the surface of the earth

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A satellite is placed in a circular orbit 600km above the surface of the earth. Find the period of the motion of this satellite.

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Solution Summary

The equation to solve the problem is stated and explained; then solved.

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There exists an equation: T^2/R^3 = (4 * Pi^2)/(G*M)

In this equation, T is the period of the satellite, R is the radius of orbit for the satellite, G is the Gravitational constant 6.67e-11 ...

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