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Gravitation: Force, motion of satellite, Kepler's law

1. A 8754-kg satellite is orbiting planet Y at an altitude of 1.69x10^6 meters above its surface and with an orbital period of 15.2 hours. If the planet has a mass of 8.19x10^24 kg, then determine the radius of planet Y.

2. Suppose the earth had another moon which was 1.69 times as far from the center of the earth as our own moon. Determine the orbital period of this moon if our own moon has a period of 27.32 days(2 pt.)

3. A 1692-kg object is located between the earth and the moon. The mass of the earth is 6.0x10^24 kg and the mass of the moon is 7.40x10^22 kg. The distance from the earth's center to the moon's center is 3.84x10^8meters . (4 pts.)The distance from the object to the moon's center is 2 times longer than the distance from the object to the earth's center. What is the net force on the object between the earth and moon.

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A 8754-kg satellite is orbiting planet Y at an altitude of 1.69x10^6 meters above its surface and with an orbital period of 15.2 hours. If the planet has a mass of 8.19x10^24 kg, then determine the radius of planet Y.

Let the mass of the planet M, that of satellite n, height of the satellite h and the radius of the satellite is R.
The distance of the satellite from the center of the planet will be R + h
Newton's law as gives force of gravity on the satellite
F = GMm/(R + h)2
This force will behave as the centripetal ...

Solution Summary

Three problems related to gravitational force, motion of satellite and Kepler's law are determined.

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