I would like to get some help in setting up this problem.
I tried using the radius of the circle as one side of the triangle but have not been able to get the answer
Please see the attached file for full problem description.© BrainMass Inc. brainmass.com February 24, 2021, 2:21 pm ad1c9bdddf
Angle MCL = beta/2
Angle LOB = 90 -beta/2
HI = radius*sin(90-beta/2) = 0.5*cos(beta/2)
GH = GI - HI
GI = A - FG = 3 - 1.0625 = 1.9375
=> GH = ML = GI - HI = 1.9375 - 0.5*cos(beta/2)
JM = 0.5*cos(90-beta/2) = 0.5*sin(beta/2)
MK = radius - JM = 0.5 - 0.5*sin(beta/2)
MC = KC - MK
KC = ...
The expert examines setting up trigonometric problems using radius of a circle.