Setting up Trigonometric Problem Using Radius of a Circle
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I would like to get some help in setting up this problem.
I tried using the radius of the circle as one side of the triangle but have not been able to get the answer
Please see the attached file for full problem description.
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Solution Preview
See attachment.
Angle MCL = beta/2
Angle LOB = 90 -beta/2
HI = radius*sin(90-beta/2) = 0.5*cos(beta/2)
GH = GI - HI
GI = A - FG = 3 - 1.0625 = 1.9375
=> GH = ML = GI - HI = 1.9375 - 0.5*cos(beta/2)
JM = 0.5*cos(90-beta/2) = 0.5*sin(beta/2)
MK = radius - JM = 0.5 - 0.5*sin(beta/2)
MC = KC - MK
KC = ...
Solution Summary
The expert examines setting up trigonometric problems using radius of a circle.
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