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Setting up Trigonometric Problem Using Radius of a Circle

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I would like to get some help in setting up this problem.
I tried using the radius of the circle as one side of the triangle but have not been able to get the answer

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Solution Summary

The expert examines setting up trigonometric problems using radius of a circle.

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See attachment.
Angle MCL = beta/2
Angle LOB = 90 -beta/2

HI = radius*sin(90-beta/2) = 0.5*cos(beta/2)
GH = GI - HI
GI = A - FG = 3 - 1.0625 = 1.9375
=> GH = ML = GI - HI = 1.9375 - 0.5*cos(beta/2)

JM = 0.5*cos(90-beta/2) = 0.5*sin(beta/2)
MK = radius - JM = 0.5 - 0.5*sin(beta/2)
MC = KC - MK
KC = ...

Solution provided by:
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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