Torque and Power
Table 1 shows a set of torque-speed measurements for a d.c. electric motor intended for use in an electric wheelchair. Data of this type is used by manufacturers to help specify motor performance.
Table1
Speed /rpm..............600..........1200......1850..........2400.......3050.........3700
Torque /Nm..............5.51..........4.53.......3.75..........2.94........2.09.........1.08
(a) Use the data in Table 1 to plot a suitable graph and obtain the five missing pieces of information, labelled (i)-(v), in the motor specification chart shown in Table 2.
Table 2
.................Stall....................No Load................Maximum Efficiency (Effic)
Operating
Volt /V.......Torque...Current....Speed.....Current...Torque....Speed...Current...Output
................./Nm....... /A.........../rpm ......./A......... /Nm....../rpm....... /A......(Effic)/%
24................(i)........140............(ii)..........5.2.........(iii).......4000.......(iv).........(v)
(b) One of the design requirements for the wheelchair states that the motor must be able to supply 40 Nm of torque at 100 rpm. Determine whether this particular motor has the power to meet that requirement.
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SOLUTION This solution is FREE courtesy of BrainMass!
Speed /rpm Torque/Nm
0 6.31
600 5.51
1200 4.53
1850 3.75
2400 2.94
3050 2.09
3700 1.08
4000 0.717
slope = -0.001
y intercept 6.31
y = -.001x + 6.31
y = -.001 ( 4000) + 6.31
0.717
y= -.001 (5000) +6.31
-0.04
The torque of motor is proportional to the current
flowing through it ( T = i)
The angular velocity of motor is proportional to the voltage across it ( w = v)
The electrical power of current I and voltage is I s Pw = T X w
Pw= power
T= Torque
w = angular velocity
Angular speed =P/T
Maximum Efficiency
Operating Stall No load Current /A Torque/Nm Speed / rpmC Current/A Output power/W Efficiency/ %
Voltage Torgue/Nm Current Speed
24 i)0.144 140 ii)6350 5.2 iii) 7.53 4000 18 iv) 30120 v) 62.99
20.37 oz -inch
Speed = P/T
T * Speed = P
T = P/Speed
T = (-20.37 /6350 * speed + 20.37
T= (-20.37 /6350* 4000 +20.37
7.538503937
Power = T X angular speed
Power = 7.53 * 4000
30120
Motor must supply 40 Nm of torque at 100 rpm.
Power = T X angular speed
Power = 40Nm X 100 rpm
Power = 4000 Watt
Divide the Speed with the load with the no load speed
% Efficiency = 4000/6350 * 100%
62.99212598
Since the motor above has a total Output Power of 30120 Watts, it should be enough to meet the requirement of above
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