Calculating the holding torque in a gear box.
A gear box has the input power 10kw at 2400 rev/min. The gear ratio is a reduction of 2 to 1. The efficiency is 98%. What is the holding torque required?
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Solution Preview
The Power to gear 1 is 10Kw. The power received by gear 2 is a little bit lower, it means, 0.98*10 Kw ( 9.8 Kw).
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Solution Summary
This full solution uses the equation Power = Torque (T) * rotational speed (w). The solution is 100 words.
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