Explore BrainMass

Explore BrainMass

    Dynamics Problem - Torque, Acceleration, and Angular Velocity

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    An electric motor is running at 1200rpm when its power is cut off for 40 seconds, then turned back on. If the rotor weighs 60lb, has a radius of gyration of 8in, and experiences a power-on net torque of 100lb/in and power-off friction torque of 8lb/in, the rotational speed in rpm of the motor 2 seconds after the power is turned back on is closest to which answer?

    a. 624
    b. 1085
    c. 21.5
    d. 114

    *Please show your work.

    © BrainMass Inc. brainmass.com October 6, 2022, 2:04 pm ad1c9bdddf


    Solution Preview

    initial rotation speed wo = 1200 rpm= 1200/60 = 20 rps = 20*2*pi= 40pi rad/s
    power cut duration t = 40 sec

    mass of the rotor m = 60 lb
    radius of gyration k = 8 in = 8/12 = 2/3 ft
    power on net ...

    Solution Summary

    This solution is provided in 168 words. It uses step by step calculations for the power off and power on phases for the system to find out angular acceleration and angular velocity.