# Integration

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Solve the initial value problem:

d²y/dx²= sec²x

y(0)=0 and y'(0)=1

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##### Solution Summary

The solution solves initial value problems by integration.

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d^2y/dx^2 = sec^2x

Integrating once wrt x we have;

dy/dx = tanx + c , where c is the constant of ...

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