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    Solve the initial value problem:
    d²y/dx²= sec²x
    y(0)=0 and y'(0)=1

    © BrainMass Inc. brainmass.com March 4, 2021, 5:39 pm ad1c9bdddf

    Solution Preview

    d^2y/dx^2 = sec^2x

    Integrating once wrt x we have;

    dy/dx = tanx + c , where c is the constant of ...

    Solution Summary

    The solution solves initial value problems by integration.