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    Algebra: Graphing, Distance between Points and Equations of Line

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    Can you please help me with the following circled problems?
    Page 187

    1. a) 12, b) 14, c) 16, d) 18 (Check for all four of our symmetries SY, SX, SO, SI; consult in WEEK7 NOTES, in COURSE CONTENT. Practice graphing these using the downloaded graphing utility GraphCalc.)

    2. a) 20, b) 24
    3. 28
    4. 32

    P. 203

    5. a) 22, b) 24
    6. a) 26, b) 30
    7. a) 36, b) 42

    P. 219

    8. a) 8, b) 18
    9. a) 36, b) 38
    10. a) 46, b) 54, c) 58, d) 64, e) 78

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    https://brainmass.com/math/graphs-and-functions/algebra-graphing-distance-between-points-equations-line-17005

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    Solution Preview

    P187.

    12.)
    y = 1/2 x + 1 has no symmetry about either x-axis or y-axis or origin.
    (see attached file). --Answer

    14.)
    y = 2x is unsymmetric about either x-axis or y-axis or origin. --Answer

    16.)
    |y| = -x
    for y> 0 => y = -x
    for y < 0 => -y = -x => y = x
    => symmetric about y-axis --Answer

    18.)
    y = -x => symmetric about origin.

    20.)
    Distance between points (-6,4) and (2,-1)
    s = sqrt ((-6 - 2)^2 + (4 - (-1))^2)
    s = sqrt((-8)^2 + (5)^2) = sqrt(64 + 25) = sqrt(89) --Answer

    24.)
    C =(x1,y1) =(0,0); r = 6
    eqn of circle,
    (x-x1)^2 + (y-y1)^2 = r^2
    => (x-0)^2 + (y-0)^2 = 6^2
    => x^2 + y^2 = 36 --Answer

    28.)
    C(-1,-3) = (x1, y1) ; r = sqrt(5)
    Eqn of circle,
    (x - x1)^2 + (y - y1)^2 = r^2
    => (x - (-1))^2 + (y - (-3))^2 = (sqrt(5))^2
    => (x + 1)^2 + (y + 3)^2 = 5
    => x^2 + 2x + 1 + y^2 + 6y + 9 = 5
    => x^2 + Y^2 + 2x + 6y + 5 = 0 --Answer

    32.)
    Figure shows the symmetry about y-axis only --Answer(B)

    P203.)

    22.)
    slope (m)= -1, y-intercept (c)= 7
    Eqn of straight line:
    y = mx + c
    => y = -1*x + 7
    => x + y = 7 ...

    Solution Summary

    Graphing problems involving linear equations are answered.

    $2.19

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