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    Newton's law of cooling relating to differential equations

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    At 10:00 AM, an object is removed from a furnace and placed in an environment with a constant temperature of 68 degrees. Its core temperature is 1600 degrees. At 11:00 AM, its core temperature is 1090 degrees. Find its core temperature at 5:00 PM on the same day.

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    Solution Preview

    The setup is y=Ce^(kt)+68
    Then C=1532 when you plug in t=0
    Then you find k. ...

    Solution Summary

    Core temperature is found using Newton's Law of Cooling and differential equations.