Explore BrainMass

Newton's Law of Cooling: Differential Equations

This content was STOLEN from BrainMass.com - View the original, and get the already-completed solution here!

Two identical cups of coffee are poured at the same time into two identical cups. Into one cup is added a teaspoon of cream at Tc which is less than room temperature. !0 minutes later the temperature of this coffee is measured.

The second cup is allowed to sit for 10 minutes and then the cream, at Tc, is added to this cup and the temperature measured.

Which cup has the higher temperature?

Ignore radiation losses
Specific heat of cream and coffee is 1
The ambient temperature of the Room is R and is constant
The masses of the coffee cups can be ignored
The amount (mass) of cream and coffee is identical in both cases.

mc = mass of cream, MC = mass of coffee

Using Newton's law of cooling solve the resulting differential equations to find the solution.

© BrainMass Inc. brainmass.com October 17, 2018, 1:09 am ad1c9bdddf

Solution Summary

Newton's law of cooling is briefly illustrated in this solution.

Similar Posting

Differential Equations and Newton's Law of Cooling

At 4:30 PM on Monday, a Virginia criminalist was called to the scene of a homicide. She noted that the body temperature of the deceased was 85.5 deg. while the air temperature was 78 deg. Thirty minutes later, the deceased's body temperature was 82 deg. Assuming the air temperature stayed constant, what is the estimated time of death of the body? (Assume a normal body temperature of 98.6 deg)

View Full Posting Details