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    Calculus Test - 10 Basic Problems

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    I need the full calculations as well as the answers. If I can see how you got from A to B to C I can figure it out, just the answers wouldn't help.10 basic problems.

    Find the First Derivative

    K(x)= 1/ (x^4)-(x^2)+1

    G(t)= square root of 6t+5

    G(x)= 6/[(3x^2)-1]^4

    F(r)=[(r^2)-(r^-2)]^-2

    Find the Limit

    lim x^2/sinx
    x->0

    lim [(x^2)+sin^2x]/4x^2
    x->0

    Find the First Derivative

    G(r)= square root of t+cos^2r

    F(x)=sin^2(4x^3)

    H(t)=(1+sin3t)^3

    F(x)=x^2cot2x

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    https://brainmass.com/math/basic-calculus/derivatives-trigonometry-functions-287479

    Solution Preview

    Find the First Derivative

    K(x)= 1/ (x^4)-(x^2)+1
    K(x) = 1/(x^4 - x^2 + 1) = (x^4 - x^2 + 1)^-1
    Let x^4 - x^2 + 1 = u
    K(u) = u^-1
    dK/du = -u^-2
    du/dx = 4x^3 - 2x
    dK/dx = dK/du * du/dx = u^-2 * (4x^3 - 2x) = 2x(2x^2 - 1)/(u^2) = 2x(2x^2 - 1)/ (x^4 - x^2 + 1)^2

    G(t)= square root of 6t+5
    G(t) = Ö(6t + 5)
    Let 6t + 5 = u
    G(u) = Öu
    dG/du = 1/2Öu
    du/dt = 6
    dG/dt = dG/du * du/dt = (1/2Öu)6 = 3/Öu = 3/Ö(6t + 5)

    G(x)= 6/[(3x^2)-1]^4
    G(x) = 6(3x^2 - 1)^-4
    Let 3x^2 - 1 = u
    G(u) = 6u^-4
    dG/du = 6(-4) u^-5 = -24/(u^5)
    du/dx = 6x
    dG/dx = ...

    Solution Summary

    The expert examines multiple derivatives and trigonometry functions. Complete, Neat and Step-by-step Solutions are provided in the attached file.

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