Derive an expression for the closed loop transfer function
Not what you're looking for?
Derive an expression for the closed loop transfer function:
h(s) = Y(s)
----
R(s) for a gain k = 10.
Work i have done so far:
Ea(s) = R(s) - B(s) = R(s) - H(s)Y(s)
Because the output is related to the actuating signal by G(s), we have
Y(s) = G(s) Ea(s)
Therefore:
Y(s) = G(s) [R(s) - H(s)Y(s)]
Now, solving for Y(s), we obtain:
Y(s) [ 1 + G(s)H(s) ] = G(s)R(s)
Therefore the transfer function relating the output Y(s) to the input R(s) is:
Y(s) = G(s)
---- -------------------------------
R(s) 1 + G(s) H(s)
Now, as the gain is equal to 10, I'm not sure if i have to just substitute that value into the last equation or not?
Purchase this Solution
Solution Summary
The solution derives an expression for the closed loop transfer function (see attachment).
Purchase this Solution
Free BrainMass Quizzes
Graphs and Functions
This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.
Multiplying Complex Numbers
This is a short quiz to check your understanding of multiplication of complex numbers in rectangular form.
Geometry - Real Life Application Problems
Understanding of how geometry applies to in real-world contexts
Solving quadratic inequalities
This quiz test you on how well you are familiar with solving quadratic inequalities.
Know Your Linear Equations
Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.