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# Chemical equation with 7 parts

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Using the balanced chemical equation:
C*6H*12O*6 + 2H(positive charge)--> C*6H*14O*6
A. How many grams of C*6H*12O*6 equals one mole?
B. How many grams of C*6H*14O*6 equals one mole?
C. How many moles of H(positive charge) react with 1 mol of C*6H*12O*6?
D. How many grams of C*6H*12O*6 react with 1 mol of H(positive charge)?
E. How many grams of C*6H*14O*6 should be formed from the reaction of C*6H*14O*6 should be formed from the reaction of C*6H*12O*6 and H(positive charge)?
F. If the reaction only produces 6.0 g of C*6H*14O*6, calculate the percent yield of C*6H*14O*6.
G. What is the maximum number of molecules of C*6H*14O*6 that can be formed in this reaction?

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C6H12O6 + 2H(positive charge)--&gt; C*6H*14O*6

a) This is asking for the molar mass of C6H12O6

C6H12O6 = 6(12.0 amu) + 12 (1.0 amu) + 6 (16.0 amu) = 180.0

180 gm of C6H12O6 implies one mole --Answer

b)Here we have two more H atoms ===&gt; 180+2 = 182gm/mole

182gm of C6H12O6 implies 1 mole of this compound

c)Since the equation is ...

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