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    Balancing/Redox

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    SeO4)-2+BrO-1-->BrO4)-1+SeO2

    How do I balance these atoms?
    How do I get the reactant charge and the product charge and the total charge?

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    Solution Preview

    The following is the balanced equation in mass.

    BrO- + 3H2O ---> BrO4)-1 + 6H+

    We know need to balance it in charge. Always do mass then charge. We see we have -1 charge on the left from the BrO-. There is a -1 charge from the BrO4)-1 and +6 charge from the 6H+ on the right. We add these together to give us a +5 charge on right. So in order to balance the ...

    Solution Summary

    This solution comprises of a concise step by step illustration of how to balance atoms, and how to determine the reactant charge, product charge and total charge.

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