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    Why more substituted alkenes are more stable than less substituted alkenes

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    Is it possible to determine why more substituted alkenes are more stable. Either by a mathematical formula (not dH that only gives a number for how strong the bonding is but a formula that takes proton and electron forces inte account) or by explaining how the electrons and protons align in a manner that makes it harder to break more substituted pi bonds of alkenes because of electrostatic forces.

    A little more details are in the attachment in identical files in pdf and word format.

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    https://brainmass.com/chemistry/reaction-intermediates-and-mechanisms/substituted-alkenes-stable-575654

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    Consider the mono and disubstituted alkenes shown above. The main accepted reason for stability is based on what we refer to as secondary orbital interactions. You know that p-p orbital overlap results in a pi-bond and that the methyl groups C-H bonds are sp3 orbitals. The C=C bond is fixed but the C-H bonds can be rotated. Because C=C bonds are shorter, ...

    Solution Summary

    A qualitative explanation is given explaining why more substituted alkenes are more stable than less substituted alkenes.

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