Please answer step-by-step with solutions:
A 150.0 iron bar at 330 degrees C is put in 1.00 kg water at 20.0 degrees C. What is the final temperature of the bar?
(Hint: bar and water will be the same at the end.)
Cs = 0.45J/(grams degree C) for iron
Cs = 4.18J/(grams degree C) for water
Assuming all of the heat released from the iron bar absorbed by water, you can than set up the following two equations:
For the heat released by the iron ...
The solution is given step-by-step to solve for T2.