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# enthalpy change for the reaction

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1) Calculate the enthalpy change for the reaction:
P4O6(s)+2O2(g)>>P4O10(s)
given the following enthalpies of reaction:
P4(s)+3O2(g)>>P4O6(s) deltaH = -1640.1 kJ
P4(s)+5O2(g)>>P4O10(s) deltaH = -2940.1 kJ

2) From the enthalpies of reaction:
H2(g)+F2(g)>>2HF(g) deltaH = -537kJ
C(s)+2F2(g)>>CF4(g) deltaH = -680kJ
2C(s)+2H2(g)>>C2H4(g) deltaH = +52.3kJ
calculate the deltaH for the reaction of ethylene with F2:
C2H4(g)+6F2(g)>>2CF4(g)+4HF(g)

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#### Solution Preview

The Hess's law states that the energy change for any chemical or physical process is independent of the pathway or number of steps required to complete the process provided that the final and initial reaction conditions are the same.

1) Reversing the equation P4(s)+3O2(g)>>P4O6(s) deltaH = -1640.1 kJ , ...

#### Solution Summary

The solution shows hot to calculate the enthalpy change for the reaction.

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