Calculate the enthalpy change for the reaction
P4O6+2O2 --> P4O10
given the following enthalpies of reaction:
P4+3O2 --> P4O6 Delta H= -1640.1
P4+5O2 --> P4O10 Delta H= -2940.1
The first thing we want to do is to reverse the first reaction and make it,
P4O6 ---> P4+3O2 Delta H= 1640.1
Notice that we had to ...
The solution calculates the enthalpy change for the reaction.