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enthalpy for the combustion of pentane

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1)The combustion of pentane,C5H12, occurs via the reaction:
C5H12(g)+8O2(g)>>5CO2(g)+6H2O(g)
with heat of formation values given by the following table:

SUBSTANCE Î"H?f(kj/mol)
C5H12 (g) -35.1
CO2(g) -393.5
H2O(g) -241.8

Calculate the enthalpy for the combustion of pentane
Express your answer in kilojoules using four significant figures.

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The solution show how to calculate the enthalpy for the combustion of pentane in detail.

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The heat of formation is 0 for O2.

By Hess's law, the Î"H for a single reaction can be calculated from the difference between the heat of formation ...

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