# Calorimetry Pre Lab

Assume you use calorimetry to calculate the specific heat capacity of a 125.24 g piece of unknown metal. You intially heat the metal to 100.0 Â°C in boiling water. You then drop the chunk of metal into a calorimeter containing 47.22 g of water at 19.7 Â°C. After closing and stiring the calorimeter thoroughly, the metal and water both come to equilibrium at a temperature of 27.6 Â°C.

Part A

What is the temperature change of the water?

100.0 Â°C

19.7 Â°C

7.9 Â°C

Part B

What is the temperature change of the metal?

-72.4 Â°C

125.2 Â°C

-27.6 Â°C

Part C

How much heat was gained by the water? (calculate the qwater)

33.1 J

1561 J

418.4 J

Part D

Knowing the above, what must qmetal?

-33.1 J

-1561 J

-125240 J

Part E

Then what must the the Specific Heat of the metal be?

0.4184 J/gÂ°C

25.00 J/gÂ°C

0.1721 J/gÂ°C

https://brainmass.com/chemistry/experimental-design-and-methods-in-chemistry/calorimetry-pre-lab-228782

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