Assume you use calorimetry to calculate the specific heat capacity of a 125.24 g piece of unknown metal. You intially heat the metal to 100.0 °C in boiling water. You then drop the chunk of metal into a calorimeter containing 47.22 g of water at 19.7 °C. After closing and stiring the calorimeter thoroughly, the metal and water both come to equilibrium at a temperature of 27.6 °C.
What is the temperature change of the water?
What is the temperature change of the metal?
How much heat was gained by the water? (calculate the qwater)
Knowing the above, what must qmetal?
Then what must the the Specific Heat of the metal be?
This solution is comprised of answers related with Calorimetry Pre Lab.