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# Prevent energy storage in body by drinking water ?

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An athlete is given 100 g of Glucose
(C_6 H_12 O_6) of energy equivalent to 1560 kJ. He utilises 50 % of this gained energy in the event. In order to avoid storage of energy in the body, calculate the mass of water he would need to perspire. The enthalpy of evaporation of water is 44 kJ/mole.

https://brainmass.com/chemistry/energetics-and-thermodynamics/prevent-energy-storage-body-drinking-water-7977

## SOLUTION This solution is FREE courtesy of BrainMass!

Energy from 100 g of Glucose = 1560 kJ

Energy not used = 1560 * (50/100) = 780 kJ

(we must use this excess energy to convert water into vapours to avoid storage)

Amount of water = 780/44 = 17.73 mol

Mass of water to be perspired

= 17.73 * 18 = 312.48 g

18 is the molecular weight of water.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!