If an aluminum sphere has a mass of 23.01 grams and was heated to 137.0 Celsius and lowered into a cup containing 20.00 mL of water at 21.0 Celsius. The final temperature of the water and the sphere was 44.0 Celsius assuming no heat was loss calculate the specific heat of the aluminum in the sphere.
C h2o =4.184J/g-0celsius
q=m x C x ( t final - T initial) I can not figure where to input the figures to receive a logical answer
Assuming no heat loss, the amount of heat must be transfer entirely from the aluminum sphere into water. ...
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